Zerojudge b943：複數 の 指對數

Zerojudge b943：複數 の 指對數

題目大意：求 $z_1^{z_2}$ 或 $log_{z_1}(z_2)$

解法：$\text{complex}$

$\text{Code：}$

#pragma GCC optimize("O3")
#include <iostream>
#include <complex>
#include <cmath>
#include <iomanip>
#define LD long double
using namespace std;

int type;

void out (LD x, bool is) {
    if (is == 1) {
        if (-1e-10 < x && x < 1e-10) {
            cout << " + 0.000000";
            return;
        }
        if (x < 0) {
            cout << " - ", x = -x;
        } else {
            cout << " + ";
        }
        cout << fixed << setprecision (6) << x;
    } else {
        if (-1e-10 < x && x < 1e-10) {
            cout << "0.000000";
            return;
        }
        if (x < 0) {
            cout << '-', x = -x;
        }
        cout << fixed << setprecision (6) << x;
    }
}

void solve() {
    complex<LD>z1, z2;
    LD a, b;
    cin >> a >> b;
    z1 = {a, b};
    cin >> a >> b;
    z2 = {a, b};
    if (type == 1) {
        z1 = pow (z1, z2);
    } else {
        z1 = log (z2) / log (z1);
    }
    out (z1.real(), 0);
    out (z1.imag(), 1);
    cout << "i\n";
}

int main() {
    ios::sync_with_stdio (false), cin.tie (0);
    while (cin >> type && type)
        solve();
}

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